Question

f(x)=(x^2+10)(1-x^2)
find interval of increasing, decreasing, concave up, concave down, local max and min and infection point

Answer 1

Did you take the derivative?

Answer 2

Yes

Answer 3

What did you end up with?

Answer 4

2(1-x^2)-2(x^2+10)

Answer 5

That's not quite right
by the product rule
\[\frac{d}{dx}[(x^2+10)(1-x^2)] \]
\[=(x^2+10)\frac{d}{dx} [(1-x^2)] + (1-x^2) \frac{d}{dx} [(x^2+10)]\]
\[=-2x(x^2+10) + 2x(1-x^2) = 2x(1-x^2 -x^2 -10)\]
\[=2x(-2x^2 -9) = -2x(2x^2 + 9)\]