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Find the area of the base of the regular pyramid
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the base is a hexagon with sides of length 9. think of the hexagon as 6 equilateral triangles where the height is 7.79 **use pythagorean theorem h^2 = 9^2 - (4.5)^2 so Area = 6*(9)(7.79)(1/2)
so 210.33
correct approximately due to rounding
exact height is 9*sqrt(3)/2
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ok
"In approximate numeric terms, the area of a regular hexagon is 2.598 times the square of its side length". David King
I tried it and it came out approx 210
ok thank you
idk lol
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