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OpenStudy (anonymous):
Find f '(x) for the function: (9lnx)/x^4 I've gotten it to (9x^3-9lnx X 4x^3)/x^8, but I'm not sure how to simplify it further than that... help?
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OpenStudy (anonymous):
I know it will be [9(1-???)]/x^5, but I don't know what else goes in the parenthesis.
OpenStudy (anonymous):
Factor out x^3 from the numerator then reduce with denominator
OpenStudy (anonymous):
9(1-4lnx)/x^5
OpenStudy (anonymous):
Thank you! :)
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