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Mathematics 17 Online
OpenStudy (anonymous):

Can you please help me solve: 2x/(4x^2y)+x/(3xy^3)

OpenStudy (anonymous):

You need a common denominator 4x^2y and 3xy^3 would have a common denominator of 12x^2y^3 So that goes on the bottom of each fraction. To turn 4x^2y into 12x^2y^3 you would need to multiply by 3y^2 on top and bottom of the first fraction.. so the first fraction is 6xy^2 ------ 12x^2y^3

OpenStudy (anonymous):

On the second fraction... to turn 3xy^3 into 12x^2y^3 you would need to multiply the top and bottom of the second fraction by 4x so you would get 4x^2 ------- 12x^2y^3

OpenStudy (anonymous):

So now you have 6xy^2 4x^2 ------ + ---------- 12x^2y^3 12x^2y^3

OpenStudy (anonymous):

(6xy^2 + 4x^2) ------------- 12x^2y^3 but the top factors into 2x(3y^2 + 2x) ----------- 12x^2y^3 so the 12x cancels and you have 3y^2 + 2x --------- 6xy^3

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