Question

Integrate f(x) = 4x^3 + 3 on the interval [0, 2].

Answer 1

we can split this integral up as well, and that "0" part is pointless later on ;)

[S] 4x^3 dx + [S] 3 dx

x^4 + 3x | [0,2]

[ (2)^4 + 3(2) ] - [ (0)^4 + 3(0)] = ??

see I told you the zero was pointless

Answer 2

32 - 0 = 32

Answer 3

Got it! =D, but it's 22.

Answer 4

lol ..... so I cant add :)