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How would i find the volume of this right cylinder???
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volume of the big cylindre minus the volume ofthe tiny cylindre
V=((Pi)r^2h)-(Pi(r^2)h)
so 527.79- 125.66
V=[Pi(8^2)(8)]-[(Pi)2^2(8)]
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okay so than volume would = 402.13m^2
I got 1507.96
you want the volume of the big cylinder minus the little cylinder right?
yea
are you doing the calculation right? [Pi*64*8]-[Pi*4*8]
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the big cylinder would be 6 is the radius and 8 is the height
No the big cylinder has r=6+2=8
oh okay.. i was doing just 6
ok cool, you ok now?
yeah
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