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find the exact value of : cos(2 arctan(4/3))
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2 tan^-1(4/3) gives us an angle between (-pi/2,pi/2)...
its a 4-3-5 triangle, I notice that
3-4-5....but same difference lol
the cos will equal 3/5, so 2(3/6) = 6/5 that might help us
cos(cos^-1(6/5)) sounds right so cos(t) = 6/5 .... is that findable?
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or is that our answer :)
to recap...for my own sanity: cos(t) = x t = 2 tan^-1(4/3) t = 2 cos^-1(3/5) t =2 cos^-1(3/5) cos(2 cos^-1(3/5)) i now this is suppose to help me....
t/2 = cos^-1(3/5) might fit someplace
lol...i think i confused myself again
oh i figured it out the answer is -7/25, thanks for your help
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