Question

use implicit differentiation to find dy/dx:
xe^y-ye^x=1

Answer 1

yay!!! implicits

Answer 2

Dx(x e^y) = Dx(y e^x) = Dx(1)

Answer 3

I LOVE implicits!

Answer 4

x e^y y' + e^y - (y' e^x + e^x) = 0

Answer 5

lol .... me too :)

Answer 6

I am your fan

Answer 7

aww shucks....ill fan you just so you can be cool like me :)

Answer 8

x e^y y' + e^y - y' e^x - e^x = 0

if it aint got a y'...move it to the otherside

Answer 9

y' (x e^y) - y'(e^x) = e^x - e^y

Answer 10

factor out you y' and divide the rest...

Answer 11

y' [(x e^y) - (e^x)] = e^x - e^y

y' = e^x - e^y
----------
x e^y - e^x