The function f(x)= 3/4x is one-to-one. Find f^-1(x).
That's looking for the inverse of the function. What do you need to do to find an inverse?
I set x= 3/4 * y and then solved for y and got x / (3/4)...then I multiply x but the reciprocal and get.... is it 4/3x?
Should be the same as what you started with.
To find the inverse, all you have to do is switch the places of the y and x :) , first we have the following: y = 3/4x the inverse is: x = 3/4y then solve ^_^
correct me if I'm wrong :)
You're totally correct.
^_^ remidia, did you understand it?
Did you guys see my second post? Haha I solved it the way you said sstarica and I got (4/3)x as my inverse
hmm, I think I forgot abt switching the numbers too , but atleas you've got it :)
So we have x=3/4y if we multiply both sides by y we get xy=3/4 then divide by x to isolate y and we get y=3/4x as the inverse, which is the same as we started with.
how did she get 4/3? lol I think it should be the same but the positions of the x and y must change, right?
I'm not sure where remidia got 4/3 from. Some algebra mistake. Not all functions have an inverse, and not all inverses switch values.
Beginning equation: y = (3/4)x ----> inverse: x = (3/4)y -----> x/ (3/4) = y -----> multiply by reciprocal (x/1) * (4/3) = y ------> gives me (4/3)x = y Make sense how I got it now
Yes, but it's not x=(3/4)y the way you had it written; it's x=(3/4y) which makes a difference. So your way is right if the original function is y=(3/4)x but if it's how you wrote it y=3/4x I take that to be y=(3/4x). So either way you have an answer and understand the process. I guess just try to clarify better. In math, it's very important how you write things. No worries though :)
Beginning equation: y = (3/4)x ----> inverse: x = (3/4)y -----> x/ (3/4) = y -----> multiply by reciprocal (x/1) * (4/3) = y ------> gives me (4/3)x = y Make sense how I got it now
it makes sense to me too I guess lol :)
Like I said, y=(3/4)x has an inverse of y=(4/3)x which is what you have. :) It was just confusing on how you initially wrote the problem.
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