Question

Im testing for concavity, the fxn

f(x) = (x^2)/(x^2-4)
f'(x) = (-8x)/(x^2-4)^2
f''(x) = -8(-3x^2-4)/(x^2-4)^3

When I set the f''= 0, I get imaginary number, what does this mean in terms of concave up or down?

Answer 1

Someone please help