Question

lnx^2=ln(20-x)

Answer 1

You mean\[\ln x^2 = \ln (20-x)\]?

Answer 2

yes

Answer 3

You can undo the logarithm by exponentiating both sides. Then\[e^{\ln x^2}=e^{\ln (20-x)} \rightarrow x^2=20-x\]

Answer 4

So\[x^2+x-20=0\]

Answer 5

Upon factoring,\[(x+5)(x-4)=0\]so either x=-5 or x = 4.

Answer 6

thanks!

Answer 7

np