Question

How would I evaluate this:
Log8 1/3

Answer 1

\[\log_{b}(x) = {\log_{k}(x) \over \log_{k}(b)} \]

Answer 2

log8(1/3)=log8(1)-log8(3)
then log8(1)-log8(3)=log(1)/log(8) - log(3)/log(8)

Answer 3

Thanks!