The Perimeter of a Rectangular house is 122 ft. The Width is 5ft less than the length. Find the length and the width.
For an equation, I wrote:
(5-w)+(5-w)+l+l=122
Now im having problems solving it.
Im not sure what Im doing wrong.
PLEASE HELP!!!
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myininaya (myininaya):
l is length
and w=l-5 where w is width
myininaya (myininaya):
2l+2(l-5)=122
OpenStudy (anonymous):
Oh, ok! I think I get it now!
That's the first part of my equation.
myininaya (myininaya):
let me know what you get for l and w
i will let you if you are right or not
OpenStudy (anonymous):
Ok thanks!
Hold on . . .
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OpenStudy (anonymous):
I think i got lost! I then got:
4l (4l)=122
Now, Im confused!
myininaya (myininaya):
ok we have 2l+2l-10=122
4l-10=122
4l=122+10=132
4l=132
l=132/4=33
so w=l-5=33-5=28
OpenStudy (anonymous):
ok wait! How did you get 10?
myininaya (myininaya):
2l+2(l-5)=122 i distribute the two
OpenStudy (anonymous):
LOL! I totally got it now!
Im laughing cuz I forgot to distribute
on my math test last week!
OK! It all makes sense now!
Thanks!
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