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cos2theta + 2cos^2theta=2
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kno any thing about square root
so we have 3cos^2theta=2
cos^2thetha=2/3
take the square root of both sides costheta=2/3 and costhetha=-2/3
thetha=arccos(2/3) and thetha=arcsos(-2/3)
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how did you get 3cos^2theta=2 if they aren't like terms so you can't combine them
oh I thought they were both raised to the second power my bad
i misread it
oh ok but do you understand it?
yes
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give me just a sec
scanning right now
thanks
so it looks good?
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yea, i got the same answer before doing it a different longer complex way but its good.
k
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