Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Ok can someone please help me do this in order, I get really confused: (7x^3-5x-3)/(x-2)

OpenStudy (anonymous):

u sure ur equation right?

OpenStudy (anonymous):

is it asking tto solve or just simplify?

OpenStudy (anonymous):

solve it in a way that I can understand it (by steps)

OpenStudy (anonymous):

(7x^3-5x-3)/(x-2)=0?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

you said solve the equation, so it must be (7x^3-5x-3)/(x-2)=0 right??? if there's only (7x^3-5x-3)/(x-2) then that is simplifying

OpenStudy (anonymous):

I know I have to do: _7x^2_______________ x-2l 7x^3-5x-3 7x^3 like dividing but I get lost after

OpenStudy (anonymous):

hmmmm I don't quite get what you've just written there. But can u check the question again pls? Because if that question's right, there'll be imaginary roots lol, which I don't think you've gone through,

OpenStudy (anonymous):

lol ok Its just Algebra I ...and I'm supposed to divide

OpenStudy (anonymous):

lol so u want the answer of the steps? :D

OpenStudy (anonymous):

YES

OpenStudy (anonymous):

here's answer: 7x^2+14x+23+43/(x-2)

OpenStudy (anonymous):

you know how to get it right?

OpenStudy (anonymous):

not really :_( like I know the 7x^2 but I get lost after that

OpenStudy (anonymous):

You know this is quite hard to explain here, better in person though. So I'd suggest u to go see ur teacher about this again. Anyway, I do it in quite a weird way so... it's better to find someone else :) or maybe some other guys here can help u, ask them. sorry abt that but really nothing I can do

OpenStudy (anonymous):

ask that guy amistre. Quite sure he can explain to u :)

OpenStudy (anonymous):

Oh its ok yeah. Thank you though :)

OpenStudy (anonymous):

oh God, I don't feel right lol. Wait me 5 mins, I'll tell you how.

OpenStudy (anonymous):

lol its fine hahaha

OpenStudy (anonymous):

I actually have to go... I'll ask my teacher tomorrow. Really thanks :)

OpenStudy (anonymous):

ok then. I'm just gonna go 2 bed

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!