Mathematics
21 Online
OpenStudy (anonymous):
How do you factor -x^3+6x^2-11x+6 ??
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
what is the problem that u r facing elaborate it
OpenStudy (anonymous):
i just need to solve it for 0.
OpenStudy (anonymous):
means that u want the RHS TO BE 0 or x be 0
OpenStudy (anonymous):
-x^3+6x^2-11x+6=0
and then solve for x
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
IV JUST WAIT FOR 2minutes
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Putting x=1 we will get:
OpenStudy (anonymous):
-1 + 6 -11 + 6 = 0
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
-12 + 12 = 0
OpenStudy (anonymous):
so it shows that x-1 is a factor of THE EQUATION
OpenStudy (anonymous):
I know the answers are 1 2 and 3. But how do factor this out is my question.
OpenStudy (anonymous):
(-x^3 + 6x^2 -11x + 6) * -1 = 0*-1
OpenStudy (anonymous):
ok now
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
x^3 - 6x^2 + 11x - 6 = 0
OpenStudy (anonymous):
x^3 = x^2(x-1) +x^2
OpenStudy (anonymous):
-6x^2 = -6x(x-1) - 6x
OpenStudy (anonymous):
11x = 11 ( x-1) + 11
OpenStudy (anonymous):
putting these values in this equation
x^2(x-1) - 5x(x-1) + 6(x-1) = 0
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
(x^2-5x+)(x-1) = 0
OpenStudy (anonymous):
(x(x-2) - 3(x-2) ) (x-1) = 0
OpenStudy (anonymous):
x-3, x-2, x-1 = 0
OpenStudy (anonymous):
x-3 = 0
x=3
x-2 = 0
x=2
x-1 = 0
x=1
OpenStudy (anonymous):
SO BYE AND REPLY ME FAST did u got it
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yeah thanks
OpenStudy (anonymous):
BYE