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2log x- log7=log112
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Do you remember your rules for adding and subtracting logs?
2logx-log7 is the same as log((x^2)/7)
i'l give you a hint to get you started. First you add log(7) to both sides. This should yield 2log(x) = log(112) + log (7). The formula for adding logs is log(x) + log(y) = log(x*y) as long as if you have same base. This is not all there is the 2 the questions, but it's a good way to start.
this is the solution\[10^{\log(784)}=x^{2}\]
which leaves you with\[\sqrt{784}=x=28\]
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