Question

how do i solve x^4-2x^3=16+8x-4x^3

Answer 1

okay. first you need to being all the terms to one side. So bring in the 16+8x - 4x^3 to the left hand side of the equation and post what you got here.

Answer 2

x^4+2x^3-8x-16=0

Answer 3

okay great. What is common in the first two terms x^4 and 2x^3?

Answer 4

x^2

Answer 5

are you sure about that?

Answer 6

no its x^3

Answer 7

okay. so factor out the x^3 in the first two terms and post what you got.

Answer 8

x^3(x+2)

Answer 9

good! next lets move on to -8x -16. what is common in those two terms?

Answer 10

4?

Answer 11

are you sure?

Answer 12

what is 8 times 2?

Answer 13

16

Answer 14

so its 8..

Answer 15

okay what is -8 times 2?

Answer 16

-16

Answer 17

so what can you factor out?

Answer 18

im confused..

Answer 19

-8x-16. what can you factor out here?

Answer 20

-8(x-2)

Answer 21

correct

Answer 22

no -8(x+2)

Answer 23

yes, that is correct.

Answer 24

-8(x+2) is correct

Answer 25

so the whole equation is what X^3(x+2)-8(x+2) right?

Answer 26

yea

Answer 27

im sorry, it is x^3(x+2)-8(x+2)=0

Answer 28

so what can you factor out here?

Answer 29

(x^3-8)(x+2)=0
x=-2,2 is the answer

Answer 30

thinker, I was in the middle of explaining the whole problem from beginning to end so that car could do it on his own without me thinking for him and doing his calculations for him.

Answer 31

i wanted to figure it out myself

Answer 32

that is not how he will learn.

Answer 33

ohh...sorry..just wanted to help :)

Answer 34

I understand :)

Answer 35

thanks though guys!

Answer 36

youre welcome.

Answer 37

ur welcome ! :)

Answer 38

by the way im a girl lol

Answer 39

sorry, lol

Answer 40

alright car, good luck .Look for patterns when you are asked to solve or simplify equations.

Answer 41

ok!

Answer 42

what if the problem is x/x^2-4 + 1/x+2 =3..do i solve it the same by bringing the 3 to the other side?