Question

the sum of three integers is two hundred eighty. The second number is ten less than twice the first number. The third number is four times the second number. Find the three numbers

Answer 1

f +s +l = 280

s = 2f-10

l = 4(s) = 4(2f-10) = 8f -40

f + (2f -10) +(8f -40) = 280

11f -50 = 280

11f = 330

f = 30
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s = 2(30)-10 = 60 - 10

s = 50
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l = 4(50)

l = 200
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30 + 50 +200 = 280

80 + 200 = 280

280 = 280

Answer 2

are the three numbers 30, 60, and 80

Answer 3

........

30 50 200