Question

solve by factoring. 18x^2-12x^3+2x^4=0

Answer 1

also -6x^5-5x^4z+25x^3z^2

Answer 2

you can start by factoring \[2x ^{2}\] leaving you with
\[2x ^{2}(9-6x+x ^{2})=0\]
which can be further factored
\[2x ^{2}(x-3)^{2}=0\]
leaving you with the roots
\[x={[0,3]}\]

Answer 3

It's the same idea with the second one, see if you can do it yourself :)