The company discovered that it costs $28 to produce 2 camera cases, $50 to produce 4 camera cases, and $140 to produce 10 camera cases. Using the quadratic function, find the cost of producing 12 cameras.
P = ax^2+bx+c, P is total production cost, x is number of cases. solve for a,b,c using the three values you are given,
so, 28 = 4a+2b+c 50 = 16a+4b+c 140 = 100a+10b+c
solve for a,b,c
how do i do that?
do you know how to do matrices?
no
okay 28 = 4a+2b+c ---------------------------------------->Eqaution 1 50 = 16a+4b+c ---------------------------------------> Eqn 2 140 = 100a+10b+c----------------------------------> eqn 3 do eqn 3 - eqn 1 and do eqn 2 - eqn 1 and post what you got here
still don't know how to figure it out
Can you subtract equation 1 from equation 2 and post it here?
38=12a+2b
how did you get 38?
32*
i mean 22*
ok so repost the correct equation again
22=12a+2b
okay good. Now, the same way, subtract equation 1 from equation 3
112=96a+8b
okay. Now, can you solve the set of equations 12a + 2b = 22 96a + 8b = 112 ?
can you help me with it.
okay, have you learned how to solve two equations for two unknown variables in school?
not that i can remember.
you haven't done basic algebra in school yet?
alright anyway, 12a + 2b = 22 ------------>eqnA 96a + 8b = 112----------->eqnB
do you know substitution to solve for a and b?
okay just do 4 times eqn A and post it here.
what do you mean
If you multiply both sides of equation A by 4, what do you get?
48a+2b=88
try again
that's multiplying both sides by 4.
so 2b*4 = 2b?
usually when i've done that, i've never done it to all. be more specific.
48a+8b=88
if a =4, then 4a =16 so we multiply both sides by 4. so if a+b = 4 then 4(a+b) =16
okay good, so 48a + 8b = 88--------------->eqn. C Do you notice what we did there? we multiplied equation B by 4 so that both equation A and equation C have the term 8B in them. So now subtract equation C from equation A.
i'm still completely confused
what are you confused about?
OK join me http://www.dabbleboard.com/draw?b=Guest654407&i=0&c=ce1b368e8fb4c87408d1e26d13c93f5bf92f9032 will explain in detail there
okay i'm on there
Join our real-time social learning platform and learn together with your friends!