Question

y=2x^2-3x , x=3t^2-2t , t=u^2-u what is the value of dy/du for u=2 ?

Answer 1

dy/du = dy/dx * dx/dt * dt/du
Differentiate each function and put everything in terms of u

Answer 2

its true.

Answer 3

you could also substitute u^2-u for t in x(t) and then sub in that for x in y(x) then differentiate but i thought that was messier

Answer 4

Thank you so much :)