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What is the square root of 90 times the square root of 40?
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√(90)(√(40))=60
How would you factor that problem out?
I have answered your previous post with solution
\[\sqrt{90}*\sqrt{40} = \sqrt{90*40} = \sqrt{3600} = \sqrt{36 * 100} \]\[= \sqrt{36} * \sqrt{100} = 6 * 10\]
\[\sqrt{90}\times \sqrt{40}\]
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polpak plz ....if u can help me.......c ma quesn
How would you do this problem: square root of 3x times the square root of 8x to third power?
The same way. Multiply the stuff under the radical, then pull out squares.
Start by multiplying the things under the radical, what do you get? \[\sqrt{3x}*\sqrt{8x^3} = \sqrt{???}\]
24xto the 4th
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Right. So \(x^4 = (?)^2\)
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