Factor 25ab-5bc-15xa+3xc.
might have to group it strategically
(25ab-5bc) + (-15xa+3xc)
5b(5a-c)-3x(5a-c)
5b(5a -c) + 3x(-5+c)
yeah, factor out a -1 to even things up :)
which then becomes, (5b +3x)(5a-c)
i have a hard time factoring
LOL good teamwork ;)
:)
so can you guys help me with my other questions
: )
factoring takes practice practice practice....
ill let superhero help you out hes good at breaking things down :)
completly agreed it doesnt just come,...u need to practice many many problems, even some ur teacher dont assign (only if u have trouble understanding)...its always about simplifying things...always look for common factors, and elements.
....yall need to hurry up and superhero with me...i feel so alone ;)
Factor n2 + 14n + 49
lol;), soprettyjess, dont go posting ur entire hwrk online u should try and learn not get all the asnwers from nybody. do one at a time take peoples advice instead of letting everybody else do the work for you :S...ur not going to learn that way
i am , im doing some on paper
thanks anyway
im just posting the ones im having a hard time with
im just saying...were not going to be here when ur test or exam comes.
kk, then thats fine then.
um yea
for the one u posted: n2 + 14n + 49, u simply ground ur terms,...ask urself wat times wat = 49 and when added is equal to 14... that value is 7... therefore ur answer to that is simply (n+7)^2
dunno why i wrote ground...
but nyway thats how u do it.
okay , its just taking me time to understand thats all .
thats fine :) hope we can help :)
i didnt mean to accuse you of posting all ur hwrk, its becuz someone did that earlier today so i was like not aggainnn. haha.. gl with everything :)
its okay ,and yea people do it all the time , im just doing some problems my mom got for me
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