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OpenStudy (anonymous):
Some help please? I've already tried it but... 1/(3x-2)+5/x=0....thanks
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OpenStudy (anonymous):
Are you trying to solve for x?
OpenStudy (amistre64):
\[\frac{1}{3x-2} + \frac{5}{x}\]
OpenStudy (amistre64):
right?
OpenStudy (amistre64):
you pretty much cross multiply at this point to get x +15x -10 = 0 ---------- yadayada x +15x -10 = 0 16x -10 = 0 x = 10/16 = 5/8
OpenStudy (amistre64):
\[x(1) + 5(3x-2) = 0\]
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