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What is the area of a trapezoid in which b1= 3a, b2=6a, and h=(10+4c)?
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area of a trapezoid is ((b1+b2)/2) * h. Or the average of the top and bottom lengths, times the height. in this case that's 4.5a * (10+4c), or 45a + 18ac. I got the 4.5a by averaging (3a+6a) / 2.
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