Question

A. x = 2
B. x = 2.5
C. x = -1
D. x = 0.5

Answer 1

So what's the question?

Answer 2

x^2-3x=-5/4 Which choices are solutions to the following equation?

Answer 3

Have you tried using the quadratic equation?

Answer 4

no how ?

Answer 5

this is the quadratic:\[-b \pm \sqrt{b ^{2}-4ac}/2a\]

Answer 6

is it -1

Answer 7

sorry it didnt come out right
http://en.wikipedia.org/wiki/Quadratic_equation

Answer 8

no its going to be two values

Answer 9

so you first want to set the given equation =0 kk? How do you do that?

Answer 10

yea -1 and 2

Answer 11

do wht .

Answer 12

\[x ^{2}-3x+5/4\]

Answer 13

all that =0

Answer 14

wht ? confused .

Answer 15

whts tht equation for .

Answer 16

kk wait

Answer 17

okay

Answer 18

\[ax ^{2} + bx + a =0 \]
where you plug is a b c in the quadratic equation
\[(-b \pm \sqrt{b ^{2}-4ac})/(2a)\]

Answer 19

to get to values

Answer 20

can you tell me the answer please .

Answer 21

in this case a=1 b=-3 a=5/4

Answer 22

umm just plug it in I gave you want to plug in

Answer 23

it didnt give me no answer

Answer 24

just plug in x =2, x = 2.5, x = -1 and x = 0.5 in the equation and see which value solves it. That will be your answer.

Answer 25

im still aint geting no answer something wrong

Answer 26

put x = 2 in \[x ^{2}-3x = -5/4\]

Answer 27

you will get \[2^{2}-3*2 = -5/4 => 4-6 = -5/4=>-2=-5/4\]

Answer 28

idk can i have the answer please .

Answer 29

-2 is obviously not equal to -5/4. so x = 2 is not the answer. similarly put x = 2.5, x = -1, x = 0.5 in the equation and see which one solve the equation

Answer 30

No, i can't do your problem for you. I can only show you how to do your problem

Answer 31

well , i dont know how to do this so . its only right if you do .

Answer 32

I showed you how to do it. just follow the steps.

Answer 33

rd can you tell me how to put it in the calculator .

Answer 34

Do you you know how to square things?\[X^2 \] ?

Answer 35

yess that = 1/2

Answer 36

no \[x^2 = x \times x\]

Answer 37

1/4

Answer 38

so just replace x with the given values and if the the equation makes sense then it works.

Answer 39

Do you know how to multiply and subtract?

Answer 40

yeaa

Answer 41

then just replace X with all the given values

Answer 42

and if the equation makes sense then thats one of the answers

Answer 43

so you sayinq 1/4 subtract all choices .

Answer 44

how did you get 1/4

Answer 45

1/2*1/2

Answer 46

well i got -1 thts the only answer i got

Answer 47

but its two answers

Answer 48

why is it two answers?

Answer 49

- 1 and 0.5

Answer 50

then you must have done some calculation wrong. Post what you got when you substituted x = 0.5

Answer 51

After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?

A. http://media.apexlearning.com/Images/200712/03/a43220e6-97e8-4d20-a14d-11fd1ac1fc7f.gif

B. http://media.apexlearning.com/Images/200712/03/c11f4c31-5d7b-4b71-8c3f-bffb49e48fa7.gif


C. http://media.apexlearning.com/Images/200712/03/fd85edd2-763d-40eb-9ae8-7b626bdac1f0.gif



D. http://media.apexlearning.com/Images/200712/03/83c6b595-efe4-4961-beb5-3e724a260a21.gif

Answer 52

cant view pics, permission denied.

Answer 53

Your reluctance to substitute the answers from using the quadratic formula is discouraging. The two answers you should of gotten were 5/2, AND 1/2.
Substituting the 5/2 into your original formula would of resulted in:\[(5/2)^{2}-15/2+5/4=0\]
25/4-15/2+5/4=0
25/4-30/4+5/4=0
0=0 5/2 is a good answer. Now check out the 1/2