Question

what is the sum of the series- (4/3)+(4/3^2)-(4/3^3)+(4/3^4) ...

Answer 1

a=4/3 , r= 1/3
sum= (4/3) / ( 1- 1/3)
= (4/3)/ (2/3)
= 2

Answer 2

but apparently the answers supposed to be 5/3 ...?

Answer 3

check it out http://www.wolframalpha.com/input/?i=%284%2F3%29%2B%284%2F3^2%29%2B%284%2F3^3%29%2B%284%2F3^4%29+...+

Answer 4

ohh, but ours for some reason has subtraction as well.

Answer 5

you mean the first term and third term and so on are negative???

Answer 6

no, the third, fifth, etc.

Answer 7

a=4/3 , r= -1/3
sum= (4/3) / ( 1+ 1/3)
= (4/3)/ (4/3)
= 1

Answer 8

mmm...i got better solution

Answer 9

4/3 + [(4/9)/ (1+4/3)]