Question

the circle C has eqn (x-3)^2+(y-4)^2=25 and the eqn of tangent at the point (6,8) is y=4/3 x ......calculate the co-ordinates of the point of intersection of C with the straight line y=2x+3

Answer 1

put y=2x +3 in the equation of circle to get the values of y

Answer 2

(x^2+9 - 6x) +(2x-1)^2 =25

Answer 3

x= -1, 3 on solving

Answer 4

now put these values in y

Answer 5

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Answer 6

already fanned u

Answer 7

thanx

Answer 8

the points P and Q have position vectors relative to the origin O given respectively by p=-i+6j and q=3i+8j.....a)calculate in degrees the size of the acute angle between p and q...b)calculate the area of triangle POQ