Question

a room has a perimeter 48 ft. the width is 2/3 of length. what is the dimensions of the room?

Answer 1

width = (2/3)x
length = x
x times (2/3)x = 48
(5/3)x = 48
5x = 144
x = 28.8
therefore length = 28.8
width = 19.2
double check my math but that is the way u solve it

Answer 2

ya i did something wrong i multilied wrong but same concept

Answer 3

It should be 2*x + 2*(2/3)x = 48, because we are looking for the perimeter. What you did was find the area instead.10/3*x = 48 -> x = 14.4.