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How would you factor x^4-81? I need to see the steps; I have the answer but not how you get it.
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\[x^4-81=(x^2)^2-9^2=(x^2-9)(x^2+9)\] \[=(x-3)(x+3)(x^2+9)\]
Thanks!
That was pretty nice. I would fan you, Anwar, if not for you getting so cheeky earlier!
Newton is a fan of me.. YAAY!! :)
When was I cheeky? I am never cheeky, if I know what that means :P
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