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Mathematics 16 Online
OpenStudy (anonymous):

An object moving vertically is at the given heights at the specified times. Find the position equation s = 1 2 at2 + v0t + s0 for the object. At t = 1 second, s = 32 feet At t = 2 seconds, s = 32 feet At t = 3 seconds, s = 0 feet

OpenStudy (amistre64):

are your numbers correct?

OpenStudy (amistre64):

and can you format the question better, its hard to make out what you are asking

OpenStudy (amistre64):

-16x^2 + 48x + 0 ; is what I get from the data

OpenStudy (anonymous):

can you post the equation separately? is it \[s = 1/2at ^{2}+v _{0}t+s _{0}\] ?

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