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Mathematics 7 Online
OpenStudy (anonymous):

simple trig identity! solve! sin^2x-cos^2x-tan^2x=2sin^2x-2sin^4x-1/1-sin^2x

OpenStudy (anonymous):

can you include parenthesis please?

OpenStudy (anonymous):

sin^2x-cos^2x-tan^2x=(2sin^2x-2sin^4x-1)/(1-sin^2x)

OpenStudy (anonymous):

so are we proving that these are equal?

OpenStudy (anonymous):

yeah, exactly

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