I need to consider this problem.. \[3x ^{2}+x-5=0\] And then use discriminant \[b ^{2}-4ac\] and then solve with the formula \[x=-b + or - \sqrt{b sqar-4ac} a\]
OpenStudy (anonymous):
haha morse code?....
OpenStudy (anonymous):
sorry that took so long, idk how to do the formula right on this thing.. does it kinda make sense though?
OpenStudy (anonymous):
ok so the squared part of that is all over 2a
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OpenStudy (amistre64):
it makes sense :)
OpenStudy (anonymous):
lol ik haha
myininaya (myininaya):
do you mean \[x=(-b+\sqrt{b^2-4ac})/2 \] and \[x=(-b-\sqrt{b^2-4ac})/2 \]
OpenStudy (amistre64):
the discriminate gives us a +number, so there are 2 solutions
myininaya (myininaya):
why does it put the a so close to the x? its hard to read
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myininaya (myininaya):
to c*
OpenStudy (amistre64):
-1/6 +- sqrt(61)/6
myininaya (myininaya):
yay i left out the time a in the denominator lol
OpenStudy (anonymous):
sorry my computer was being slow so everything you guys said just loaded.
OpenStudy (anonymous):
I left off with \[-1\sqrt{-59} all \over 6\]
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OpenStudy (anonymous):
minus the all
OpenStudy (anonymous):
so i'm not sure if i do something with i at this point..or if that is even correct what I have.. if that was the answer someone gave up there I guess I'm not sure what that's supposed to look like typed out