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Find a particular solution to the differential equation: 2y'' - 1y' - 1y = -1t^2 + 2t + 3exp(3t)
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divide each term by 2 and then proceed as normal using undetermine coefficients or variation of parameters
Thanks. I already know to use either method. I'm just not sure about the answer
you can always use wolfram alpha if you want to check the final solution
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