Question

solve the following differential equation for y: (d^2y/dx^2)=e^(-dy/dx), y'(0)=1, Y(0)=e

Answer 1

without the initial conditions I got y=xlnx-x+C

Answer 2

it satisfies the differential equation but the initial conditions will not work because ln(x) dne at x=0. so maybe they are looking for a different y. I don't know how to find that y