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could someone double check my answer for this quadratic equation!?
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\[3x ^{2}-1=x\]
I got 1+ or - sqrt -11 over 6
\[1 + or - \sqrt{-11}\over 6\] little better to understand here
thats right except it should be positive 13 under the radical
positive 13 instead of the -11? or positive 13 where the 6 is?
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also, are there 2 non real, or real answers?
it should be: [1+/- sqrt(13)]/6
they are both real answers
ok awesome. thanks!
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