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OpenStudy (anonymous):
How do you find the exact solution of: log(x+3)+log(x)=1
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OpenStudy (anonymous):
log(x^2+3x)=1 x^2+3x=e x^2+3x-e=0
OpenStudy (anonymous):
did u like the answer?
OpenStudy (anonymous):
I don't really understand it actually. I don't know what the e is..
OpenStudy (anonymous):
e is an exponential number e=2.7 (approx.)
OpenStudy (anonymous):
Ok so the answer is that last line or zero?
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OpenStudy (anonymous):
zero ??? use the quadratic formula to solve for x... what grade r u in?
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