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Does a=-1, b=-24, and c=144 of this quadratic equation?
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\[-y ^{2}=-24y+144\]
y^2-24y+144=0 (y-12)(y-12)=0 y=12,12
y2-24y+144 so YES!
ax2+bx+c
a=1
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I have to put what a, b and c are but i wasn't sure if any of these change to positive or if it is just how it looks.
they need to be on the same side with 0 on the other
so NO...either side, some are off
you got it
THanks! I haven't solved it yet but it looks like someone up there got 12, maybe that's the only repeating answer?
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yes answer is 12 if you solve it
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