http://img862.imageshack.us/i/page596.jpg/
I need help # 37,38
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OpenStudy (anonymous):
Which one do you want to tackle first?
OpenStudy (anonymous):
37 first
OpenStudy (anonymous):
Ok, what do you know about the length of AD?
OpenStudy (anonymous):
the answer is d, How I can find the length?
OpenStudy (anonymous):
What can you tell me about the length of AD by looking at the picture?
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OpenStudy (anonymous):
the question is what the measure of AD?
OpenStudy (anonymous):
Yes I know. I'm asking what you think about the problem
OpenStudy (anonymous):
can you see the picture?
OpenStudy (anonymous):
This is math. Some thinking is required ;)
OpenStudy (anonymous):
Yes I can see it. I'm asking what does it tell you? I know what it's telling me.
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OpenStudy (anonymous):
yes it math
OpenStudy (anonymous):
given the lenghth AB, BC, CD, I don't get what you asking
OpenStudy (anonymous):
I wonder do you know how to get answer find length AD
OpenStudy (anonymous):
I know how to get the answer yes. I want to know what you know? That way I can see how to help you.
OpenStudy (anonymous):
Nobody cares if I can do it.
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OpenStudy (anonymous):
I don't know
OpenStudy (anonymous):
if given radius is may easy for my to do
OpenStudy (anonymous):
I been thinking many hours but I can't solve
OpenStudy (anonymous):
if you can help me ,
OpenStudy (anonymous):
Good! You know how to solve it with the radius?
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OpenStudy (anonymous):
yes, I can do if I know radius or given tangents or secants
OpenStudy (anonymous):
Ok, well for this we don't actually need the radius. This is called a tangential quadrilateral. It has the property that the two opposite sides will add to the same length.
OpenStudy (anonymous):
what side?
OpenStudy (anonymous):
AB + CD = AD + BC
OpenStudy (anonymous):
great, thank
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OpenStudy (anonymous):
What do you think about 38?
OpenStudy (anonymous):
let me think
OpenStudy (anonymous):
I think H
OpenStudy (anonymous):
Why?
OpenStudy (anonymous):
w is the weight the total weight have to be less or equal
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OpenStudy (anonymous):
r no more than 12
OpenStudy (anonymous):
r no more than 12 comes from what statement?
OpenStudy (anonymous):
If I tell you, there are 4 reams of paper in the box, what is the weight w?
OpenStudy (anonymous):
the given r is the box can carry no more than 12 reams of paper
OpenStudy (anonymous):
right.
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OpenStudy (anonymous):
so my r is less than 12 it's 4, what is w?
OpenStudy (anonymous):
4.4
OpenStudy (anonymous):
if the box itself weighs 1.3 and each ream weighs 4.4 and there are 4 reams, what is the total weight?
OpenStudy (anonymous):
total; 18.9 w
OpenStudy (anonymous):
You sure the weight isn't 1 ?
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OpenStudy (anonymous):
22.8w
OpenStudy (anonymous):
I think 18.9 was correct actually.
OpenStudy (anonymous):
But wait, why isn't the weight just 3.1 or 1.3 or 10
OpenStudy (anonymous):
Aren't all those < 1.3 + 4.4r ?
OpenStudy (anonymous):
w<1.3 +4.4r, r<12
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OpenStudy (anonymous):
Right. So if I tell you that r=1, what is the weight? It's 1.1111111111111 right?
OpenStudy (anonymous):
because
1.111111 < 1.3 + 4.4
OpenStudy (anonymous):
r=1?
w<5.7
OpenStudy (anonymous):
Sure, and 1.1111 is less than 5.7, so 1.1111 is the weight? But 0.1274 is also less than 5.7, so which one is the weight?
OpenStudy (anonymous):
Or is the weight both 1.1111 and 0.1274 or maybe the weight is \(\pi\). I do like \(\pi\).
(Here is where you tell me I'm being dumb and the weight is 5.7)
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OpenStudy (anonymous):
\(\pi\) is less than 5.7 so I think \(\pi\) is the weight. Cause you said anything less than 1.3 + 4.4r was a solution for the weight of a box.
OpenStudy (anonymous):
and I said there was 1 ream, so the box can weigh anything less than 5.7
OpenStudy (anonymous):
And you say "No dummy the box weighs 5.7"
OpenStudy (anonymous):
;)
OpenStudy (anonymous):
ok, thank you so much
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OpenStudy (anonymous):
Wait. What? Did you find the solution?
OpenStudy (anonymous):
yes I think
w<1.3 + 4.4 r , r<12
OpenStudy (anonymous):
no.. that's what I'm trying to explain
OpenStudy (anonymous):
Once we pick an r, we know exactly how much the box weighs. The restriction is on r not on the weight.
OpenStudy (anonymous):
w is not any number less than 1.3 + 4.4r. If I tell you r =1, w is not any number less than 5.7. It is 5.7
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OpenStudy (anonymous):
the key not reqite r
OpenStudy (anonymous):
hrm? I didn't follow that. The answer is G.
OpenStudy (anonymous):
If we have r, we know exactly what w is. Not that it's less than something, we know exactly. The only restriction we have is that r must be less than or equal to 12. But will be exactly 1.3 + 4.4r for any r you pick that is allowed.
OpenStudy (anonymous):
err w will be exactly 1.3 + 4.4r
OpenStudy (anonymous):
Ok , you said w = 1.3+4.4r ,r<12
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OpenStudy (anonymous):
yes. Because once you pick how many reams in the box, the box has an exact wieght.
OpenStudy (anonymous):
if you pick 1 ream goes in the box, the box will wiegh 5.7. It will not weigh 1.1 or 0.213. If w < 5.7 were the definition then w could be any of those.
OpenStudy (anonymous):
OK, it help
OpenStudy (anonymous):
I understand now
OpenStudy (anonymous):
thank you
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