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i need to factor this problem 2r^3+4r^2-48r
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use the gcf methode and pull out a 2r from everyone of the numbers. post what you get because sometimes you have to do another process also
I am new at this sorry
(2r)(r-4)(r+6) r is going to be -6 and 4
ok if you divide each of the numbers by a 2r it's going to reduce the amount that remain. so you end up with (2r(r^2+2r+24))
Don't forget the root r=0
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