Question

Laplace Transform of 10(1-e^(-3(t-1)u(t-1)?? Need haalp

Answer 1

i told you how to solve this yesterday

Answer 2

i just not sure the difference with 10(1-e^(-3(t))u(t-1) and 10(1-e^(-3(t-1))u(t-1)??

Answer 3

its pretty much the same except you have to break the exponent into two products because for example e^2t+2=e^2t*e^2 which is similar to what happens in your problem. So the e^2 in my example simply is treated as a constant