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Use the Binomial Theorem to expand and simplify the expression. (q - 5)5 A.q^5 - 25q^4 + 250q^3 - 1250q^2 + 3125q B. q^4 - 20q^3 + 150q^2 - 500q + 625 C. q ^5 - 25q^4 + 375q^3 - 1875q^2 + 3125q - 3125 D. q^5 - 20q^4 + 225q^3 - 1125q^2 + 2500q - 3125 E. q^5 - 25q^4 + 250q^3 - 1250q^2 + 3125q - 3125
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just...use the binomial theorem: \[(x+y)^n = (n \ 0)x^ny^0 + (n \ 1)x ^{n-1}y^1 + (n \ 2)x ^{n-2}y^2 ....\]
cool thanks so I think it's e then...
you are correct good sir.
Lol thanks! I was doing my own version of the binomial theorem I guess cause I was close to the answers but not quite there!
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