In triangle ABC, a=6, b=9 and sin A=2/3. Find sin B
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OpenStudy (anonymous):
wait so a and b are sides?
OpenStudy (anonymous):
In general if A is a corner, side a is the side opposite.
OpenStudy (anonymous):
but A, B, and C are probably the sides. a, b, and c are probably the angles
OpenStudy (anonymous):
If ABC is a triangle, they are the corners/ angles, ALWAYS.
OpenStudy (anonymous):
C
/\
a / \ b
/_____\
B c A
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OpenStudy (anonymous):
C
/\
6 / \ 9
/_____\
B c sin(A) = 2/3 sin(B) = ?????
OpenStudy (anonymous):
sin A = a/c
sin B = b/c
sin A = 2/3 so a/c = 2/3 and a = 6 so
2/3 = 6/x
x = 9 so side c = 9
sin B = b/c and b = 9 and c = 9
sin B = 1
I think.....
OpenStudy (anonymous):
thats the answer I got
OpenStudy (anonymous):
what about this problem: in triangle DEF angle D =40, DE=12 meters and DF=8 meters. Find the area of triangle DEF to the nearest tenth of a square meter