Mathematics
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OpenStudy (anonymous):
how do i solve -xsquared=-5x+6
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OpenStudy (anonymous):
add x squared to both sides of the equation and post what you got.
OpenStudy (anonymous):
0=xsquared-5x+6
OpenStudy (anonymous):
now, do you know how to solve quadratic equations of the form
ax2+bx+c = 0?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
then go ahead and do that in your problem.
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OpenStudy (anonymous):
x=1
OpenStudy (anonymous):
mary, we help them get their answers, not solve their problems for them
OpenStudy (anonymous):
a=0xsquared b=-5x and c=6
OpenStudy (anonymous):
connor that is not the answer so keep working
OpenStudy (anonymous):
how did you get a = 0?
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OpenStudy (anonymous):
-xsquared=-5x+6
+x +x
-5x+6+x
-6 -6
-5x-5
/-5 /-5
x=1
OpenStudy (anonymous):
that it
OpenStudy (anonymous):
0 = x^2 - 5x + 6 that factors into
0 = (x - 3)(x - 2) do you know how to solve from here?
OpenStudy (anonymous):
sorry internet stopped working
OpenStudy (anonymous):
so -2,-1?
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OpenStudy (anonymous):
either x - 3 = 0 or x - 2 = 0
solve for x
x = 3 or x = 2
OpenStudy (anonymous):
but im supposed to get the coordinates like (blank,0) and (blank,0)
OpenStudy (anonymous):
x=1
OpenStudy (anonymous):
so -2,0 and -3,0?