a hat contains 4 marbles one red one green one blue and one yellow. two marbles are sletected at ramdon without replacment. what is the probablity that one is not yellow
Let's say that during the first drawing you do NOT pull out a yellow. That probablity is 3/4 then that marble is tossed out. Let's say that during the second drawing you DO pull out yellow.. That probablity is 1/3 because there is one yellow and only three marbles left. so 3/4 * 1/3 = 1/4 I think this is correct.
Thanks for the reply
The probability that one is not yellow = 1 - probability that one is yellow To calculate the probability that one is yellow = either the first one is yellow or the second one is yellow = (1/4 * 1) + (3/4 * 1/3) = 1/4 +3/12 = 1/2. The probability that neither is yellow = 1-1/2 = 1/2
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