Question

what is a factor of 2n*2-32n?

Answer 1

i was thinking 2n-8?

Answer 2

Do you mean 2n^2 - 32n?

Answer 3

yeah

Answer 4

Well, both of the terms have a factors of 2n, so if we pull 2n out of both we get

2n * (n-16) = 2n^2 - 32n

So a factor of 2n^2 - 32n would be (n - 16)

Answer 5

thank you!

Answer 6

no that answer is wrong it is 2n(n-16)

Answer 7

no it's n-16

Answer 8

because if it was n-16 how are you gonna get to 2n^2-32n

Answer 9

its factoring the binomial

Answer 10

No its not i have a factor calculator go to mathway.com

Answer 11

the binomial??

Answer 12

trust me its right. there are three options on my paper:
n-16
2n-8
n+4
its n-16

Answer 13

Model_chic, 2n is a factor, as well as (n-16), both are correct. It would be good form to list both factors, but either would work if they just want one factor.

Answer 14

so wouldn't it be (n-16) (n-16)

Answer 15

please tell me how you got n-16

Answer 16

Lets look at the equation. It is 2n^2 - 32n. The 2n^2 part and the 32n part have a common factor. 2n divides nicely into both of them, when we divide 2n^2 by 2n we get n, and when we divide 32n by 2n we get 16. So we can rewrite the equation like so

2n * (n-16) = 2n^2 - 32n

We can verify this is correct by multiply 2n and (n - 16) to get our original equation.

Answer 17

then it will just be 2n*(n-16) i just searched it up

Answer 18

i mean 2n(n-16)

Answer 19

Yes, but keep in mind, 2n is a factor, and (n-16) is a factor.

Answer 20

2n is also yhe gcf sp when you have your final answer the gcf will be in your answer