Question

any one good with pobability?

Answer 1

maybe..but then again.....

Answer 2

What is the probablitity of typing the word probability with no mistakes 5 times in a row?

Answer 3

well i have an assignment im not quite understanding.

Answer 4

cant read your mind...spit it out :)

Answer 5

her assignment is to find out what the probability is that you will randomly type the correct answer

Answer 6

A single card is drawn from a standard deck of cards. Find the following probabilities. A face card is a jack, queen, or king.

P(jack | red) =

P(three | not a face card) =

Answer 7

Suppose a pair of dice are rolled. Consider the sum of the numbers on the top of the dice and find the probabilities.
(a) 8, given that exactly one die came up 5.


(b) 4, given that exactly one die came up 3.


(c) 6, given that exactly one die came up 6.

Answer 8

there are 52 cards to a deck; with 4 suits and 3 face cards per suit.

12 face cards in the whole deck; 6 are red, and 6 are black

Answer 9

the probability of a red face card is 6 out of 52; (6/62) x100 for a percent

Answer 10

is it a red jack? or a jack or a red card?

Answer 11

4jack 24red cards
----- * ------------ seems right. what you think?
52 52

Answer 12

or it could mean you have a 26/52 chance of drawing either a red card or a jack.

Answer 13

would it be 6/52 or 62?

Answer 14

What does P(a|b) mean: a or b right?

Answer 15

im guessing a red jack

Answer 16

ya i believe so? where are you seeing that

Answer 17

just recalling that in programing that "|" bar means or; and after checking up on it, I was right.

Answer 18

but the chances of picking a jack versus or a red card has some issue to it, since a jack can also be a red card.

Answer 19

P(a|b) = P(a) + P(b) - P(A & B).

Answer 20

Pjack = 4/52
Pred = 26/52
Pred jack = 2/52

(4+26) - 2
--------- = 28/52
52

Answer 21

P(three | not a face card) since 3 is not a face card, both of these occur at the same time.

Pthree = 4/52
Pnot face = 43/52

4+43-4
------- = 43/52
52

Answer 22

make sense?

Answer 23

yes, just going over what you are doing so I can do it on the next problem

Answer 24

this dice one is not possible:

(c) 6, given that exactly one die came up 6.

the sum of the dice would at least have to be 7 if one is a 6. 6 + 1 = 7; so the sum being 6 between the two dice is impossible

Answer 25

Suppose a pair of dice are rolled. Consider the sum of the numbers on the top of the dice and find the probabilities.

(a) 8, given that exactly one die came up 5. Since we dont need to consider the other dice here, we should just simply figure the probability of getting a 3 on the other one. which is a 1/6 chance.


(b) 4, given that exactly one die came up 3. same logic here; ther eis a 1/6 chance of the other die being a "1"

Answer 26

Thank you for helping me and breakin it down to steps.