Question

what would the anti deriv. be of the function 7sec(4u)tan(4u)?.. got an answer but for some reason its not correct.. any help?

Answer 1

nevermind i got it ..

Answer 2

this is the one i need help with .... 5/ (1+ 25s^2)

Answer 3

That looks similar to the derivative of arctan. Which is

\[du / (1 + u^2) = (\arctan u)'\]

So know that, the u would be 5s so the answer would be arctan(5s).

\[5 / (1 + (5s)^2) = (\arctan 5s)'\]