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Mathematics 13 Online
OpenStudy (anonymous):

Factor 5z(2z+1)-2(2z+1)

OpenStudy (anonymous):

(2z + 1)(5z -2)

OpenStudy (anonymous):

i feel like i'm spamming....

OpenStudy (gw2011):

You can do this in one of two ways: 1) Since (2z+1) is being multiplied by 5z and -2, the factor is (5z-2)(2z+1) 2) This second method is the long way which is the following: 10z^2+5z-4z-2 This was done by multiplying it out 10z^2+z-2 (5z-2)(2z+1) This is factoring out the above

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